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(P)=-14P^2+1820P-50400
We move all terms to the left:
(P)-(-14P^2+1820P-50400)=0
We get rid of parentheses
14P^2-1820P+P+50400=0
We add all the numbers together, and all the variables
14P^2-1819P+50400=0
a = 14; b = -1819; c = +50400;
Δ = b2-4ac
Δ = -18192-4·14·50400
Δ = 486361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1819)-\sqrt{486361}}{2*14}=\frac{1819-\sqrt{486361}}{28} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1819)+\sqrt{486361}}{2*14}=\frac{1819+\sqrt{486361}}{28} $
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